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Render Template Without Line Breaks Using a Django Template Tag This Django block template tag renders your templates without any line breaks. Be aware, it might mess up the content of forms so I recommend using it outside of them. This is the block tag I use on Uglek to serve the site without any line breaks in the base code.

# /project/app/app_filters.py

# Imports
from django import template
from django.utils.html import strip_tags
from django.template.base import Node
from django.utils.functional import keep_lazy
import six

register = template.Library() # Register template library
def linebreakless(parser, token):
    nodelist = parser.parse(('endlinebreakless',))
    parser.delete_first_token() # Delete tags from the template
    return LinebreaklessNode(nodelist) # Render the node without line breaks

class LinebreaklessNode(Node):
    def __init__(self, nodelist):
        self.nodelist = nodelist # Initialize with nodelist

    def render(self, context):
        strip_line_breaks = keep_lazy(six.text_type)(lambda x: x.replace('\n', '')) # Using keep lazy
        return strip_line_breaks(self.nodelist.render(context).strip()) # Strip the line breaks and return the node

In action, this tag looks like
{% linebreakless %}This is some text here. This will render without a line break{% endlinebreakless %}
You can use this tag twice in your templates to render everything but the main content without line breaks, and it will save some server time serving fewer line breaks as well as make it more difficult for anyone to copy and use your code. It also could have other uses, such as removing line breaks in forms or in the text that contains too many and should be rendered only on one line. I hope this Django template filter is useful for you. Let me know if you have any questions about implementing it.

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