Render Template Without Line Breaks Using a Django Template Tag

# /project/app/app_filters.py

# Imports
from django import template
from django.utils.html import strip_tags
from django.template.base import Node
from django.utils.functional import keep_lazy
import six

register = template.Library() # Register template library
@register.tag
def linebreakless(parser, token):
    nodelist = parser.parse(('endlinebreakless',))
    parser.delete_first_token() # Delete tags from the template
    return LinebreaklessNode(nodelist) # Render the node without line breaks

class LinebreaklessNode(Node):
    def __init__(self, nodelist):
        self.nodelist = nodelist # Initialize with nodelist

    def render(self, context):
        strip_line_breaks = keep_lazy(six.text_type)(lambda x: x.replace('\n', '')) # Using keep lazy
        return strip_line_breaks(self.nodelist.render(context).strip()) # Strip the line breaks and return the node

{% linebreakless %}This is some text here. This will render without a line break{% endlinebreakless %}